Aqueous ferric chloride (FeCl3) reacts with aqueous sodium hydroxide (NaOH) lớn produce ferric hydroxide ( Fe(OH)3 ) và sodium chloride (NaCl). So, yellow-brown màu sắc solution will turn into a brown color precipitate. Color changes, precipitating, balanced reaction, ionic equation of FeCl2 + NaOH reaction are discussed in this tutorial.

Bạn đang xem: Fecl3 + naoh → fe(oh)3 + nacl ## Aqueous ferric chloride và aqueous sodium hydroxide reaction

Ferric chloride ( Iron(III) chloride ) is a soluble inorganic compound in water and form a yellow-brown solution.

Sodium hydroxide is a strong alkaline colorless solution and readily gives hydroxyl ions (OH-).

### What are the products when aqueous FeCl3 reacts with aqueous NaOH

When we địa chỉ aqueous NaOH solution lớn aqueous FeCl3 solution, brown color precipitate is formed. This precipitate is ferric hydroxide ( Fe(OH)3 ).

### FeCl3 + NaOH = Fe(OH)3 + NaCl

Above mentioned reaction is not a balanced chemical reaction. So, we need khổng lồ balance this reaction & we will vày it next section.

## How to balance FeCl3 và NaOH reaction?

This reaction is a not a redox reaction. Therefore by observing number of atoms in right side và left side, we can balance the reaction in few seconds. This method is a trial and error method. But it is so easy for like this simple equation.

### Balanced reaction & stoichiometry of FeCl3 và NaOH

FeCl3 + 3NaOH = Fe(OH)3 + 3NaCl

According khổng lồ the stoichiometry of the reaction, 1 mol of FeCl3 reacts with 3 mol of NaOH và produce 1 mol of Fe(OH)3 và 3 mol of NaCl.

### Balanced reaction of FeCl2 and NaOH with physical states

FeCl3(aq) + 3NaOH(aq) = Fe(OH)3(s) + 3NaCl(aq)

FeCl3 is soluble in water. Therefore, it exists as an aqueous solution và NaOH also exists as a solution. But, solubility of Fe(OH)3 is poor in water. Hence it deposits as a precipitate at the bottom of the reaction. NaCl is very much soluble in water & exists as an aqueous solution.

### Let's solve a problem about FeCl3 + NaOH reaction

There are two aqueous solutions. In one solution, there is 0.1 mol dm-3 FeCl3 0.1 dm3 & other aqueous solution is 0.1 mol dm-3 NaOH2 0.1 dm3. When, these two solutions are mixed with each other, how much grams are precipitated as Fe(OH)3?

Answer: First, you have khổng lồ find mixed amounts of NaOH và FeCl3.

Mixed NaOH amount = 0.01 mol Mixed amount of FeCl2 = 0.01 mol

To react with 0.01 mol FeCl3, 0.03 mol of NaOH is required according khổng lồ the stoichiometric equation. But, there is only, 0.01 mol of NaOH. Therefore, NaOH is the limited reagent.

Produced FeCl3 amount = 0.0033 mol Prodyced Fe(OH)3 mass = 0.54 g

Assumption: Amount of Fe(OH)3 in the aqueous phase is negligible compared lớn amount in the precipitate.